Software - Programming concept

Programming Concepts (C Language - Pattern Printing)

This section requires practical application of programming.

Sample Task 1: Write a C program to print the following two patterns based on a user-inputted number of rows (e.g., if the user enters 4):.

Pattern 1:

*
**
***
****

Pattern 2:

1
1 2
1 2 3
1 2 3 4

• Sample Task 2: Different Patterns

  • Task: Write a C program that takes an integer n as input and prints:
    • An inverted right-angled triangle of stars (e.g., for n=4: *_, _, *_, _).

  ****
  ***
  **
  *
  

• Sample Task 3: Number Sequences

  • Task: Write a C program that takes an integer n as input and prints the first n numbers of the Fibonacci sequence

  for n= 8
  0 1 1 2 3 5 8 13
  
  

  • Skills Tested: Loops, variable assignment, handling sequences.

• Sample Task 4: Simple Array Processing

  • Task: Write a C program that asks the user to enter 5 integers, stores them in an array, and then calculates and prints the sum and average of the numbers in the array.
  • Skills Tested: Array declaration and access, loops for input and processing, basic arithmetic operations, integer/float division for average.

Sample Answer for task 1 (C Code):.

#include <stdio.h>

int main() {
    int rows;

    // Get input from user
    printf("Enter the number of rows: ");
    scanf("%d", &rows);

    if (rows <= 0) {
        printf("Please enter a positive number for rows.\n");
        return 1; // Indicate error
    }

    // --- Print Pattern 1 ---
    printf("\nPattern 1:\n");
    for (int i = 1; i <= rows; i++) { // Outer loop for rows
        for (int j = 1; j <= i; j++) { // Inner loop for stars in each row
            printf("*");
        }
        printf("\n"); // Move to the next line after each row
    }

    // --- Print Pattern 2 ---
    printf("\nPattern 2:\n");
    for (int i = 1; i <= rows; i++) { // Outer loop for rows
        for (int j = 1; j <= i; j++) { // Inner loop for numbers in each row
            printf("%d ", j); // Print the inner loop counter 'j'
        }
        printf("\n"); // Move to the next line after each row
    }

    return 0; // Indicate successful execution
}